1194C - From S To T - CodeForces Solution


implementation strings *1300

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Python Code:

from collections import*
I=input
for _ in[0]*int(I()):
 s=1,*I(),0;t,p=I(),Counter(I());i=1
 for c in t:
  if c==s[i]:i+=1
  elif p[c]:p[c]-=1
  else:i=0
 print('YNEOS'[s[i]!=0::2])

C++ Code:

#include <bits/stdc++.h>
 
using namespace std;

//... Gmail: [email protected]
//... Facebook: https://www.facebook.com/profile.php?id=100009621791250
//... Github: https://github.com/ahnafshahrear
 
typedef long long int i64;
typedef unsigned long long int ui64;

#define vt vector
#define pb push_back
#define Size(v) (int)(v.size())
#define Full(v) v.begin(), v.end()
#define Sort(v) sort(Full(v))
#define ReverseSort(v) sort(v.rbegin(), v.rend())
#define Reverse(v) reverse(Full(v))
#define LineBreak cout << "\n";
#define pi 3.1415926535897932384626
#define pf first
#define ps second
#define mp make_pair
#define LowerBound(v, x) lower_bound(Full(v), x) - v.begin()
// First element not less than x - zero based index
#define UpperBound(v, x) upper_bound(Full(v), x) - v.begin()
// First element greater than x - zero based index
#define Mod 1000000007;

#define Boundary(r, c, row, column) ((r >= 0 && r < row) && (c >= 0 && c < column))
//... Works with zero based index
#define Exit(msg) {cout << msg << "\n"; return;}

#define optimize() ios_base::sync_with_stdio(0); cin.tie(0); cout.tie(0);
#define fraction() cout.unsetf(ios::floatfield); cout.precision(10); cout.setf(ios::fixed,ios::floatfield);
#define file() freopen("input.txt","r",stdin); freopen("output.txt","w",stdout);

template<typename T> //... cin >> vector
istream& operator>>(istream &istream, vector<T> &v) {for (auto &it : v) cin >> it; return istream;}
template<typename T> //... cout << vector
ostream& operator<<(ostream &ostream, const vector<T> &p) {for (auto &it : p) cout << it << " "; return ostream;}

template<typename T1, typename T2> //... cin >> pair
istream& operator>>(istream &istream, pair<T1, T2> &p) {return (istream >> p.first >> p.second);}
template<typename T1, typename T2> //... cout << pair
ostream& operator<<(ostream &ostream, const pair<T1, T2> &p) {return (ostream << p.first << " " << p.second);}

template<typename T>
void _debug(T a) {
    cout << a << "]\n";
}
template<typename T, typename... Args>
void _debug(T a, Args... b) {
    cout << a << ", ";
    _debug(b...);
}
template<typename... Args>
void debug(Args... b) {cout << '['; _debug(b...);}


bool sortBySec(const pair<int,int> &a, const pair<int,int> &b)
{
    return a.second < b.second;
}

int countDigit(int number) 
{
    return floor(log10(number) + 1);
}

bool isPalindrome(string s) 
{
    for (int i = 0; i < s.length() / 2; i++) 
    {
        if (s[i] != s[s.length() - i - 1]) return false;
    }
    return true;
}

void subString(string s) 
{
    for (int i = 0; i < s.size(); i++)
    {
        for (int len = 1; len <= s.size() - i; len++)
        {
            cout << s.substr(i, len) << "\n";
        }
    }
}

// Solution starts here...

void solve()
{
    string s, t, p;
    cin >> s >> t >> p;
    map<char, int> occ;
    for (char x: p)
    {
        occ[x]++;
    }
    int in = 0;
    for (char x: t)
    {
        if (x == s[in])
        {
            in++;
        }
        else if (occ[x])
        {
            occ[x]--;
        }
        else Exit("NO");
    }
    if (s.size() == in)
    {
        cout << "YES\n";
    }
    else cout << "NO\n";
}

int main()
{
    optimize()

    int testCase = 1;
    if (true)
    {
        cin >> testCase;
    }
    for (int t = 1; t <= testCase; t++)
    {
        solve();
    }
    return 0;
}


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